feat(question_gen): add v2 material sampler with family constraints
Implement sample_material_v2 module that samples tree nodes with QuestionFamilySpec-aware constraint validation, providing richer MaterialContext output (subtitles, cross-L2 context, frame paths). Key components: - AnchorContext/MaterialContext frozen dataclasses - _validate_sampling_constraints: multi-level constraint checking - _collect_subtitle_sentences: subtree subtitle extraction - _collect_cross_l2_context: peer L2 event descriptions - sample_material_v2: main entry with retry-on-constraint-violation Tests: 11 unit tests covering normal sampling, used-node exclusion, constraint violation retries, cross-L2 population, and subtitle collection. Co-Authored-By: Claude Opus 4.6 (1M context) <noreply@anthropic.com>
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"""v2 素材采样器 — 基于家族约束的树节点采样与上下文收集。
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在 v1 synthesizer 的基础上引入 QuestionFamilySpec 约束验证,
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为每次出题提供更丰富的素材上下文(字幕、跨 L2 上下文、帧路径)。
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典型调用路径::
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material = sample_material_v2(
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tree=tree_index,
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family_spec=REASONING_FAMILY,
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task_type="Causal Reasoning",
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used_node_ids=already_used,
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rng=rng,
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)
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"""
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from __future__ import annotations
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from dataclasses import dataclass
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from typing import TYPE_CHECKING
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from loguru import logger
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if TYPE_CHECKING:
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import random
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from app.question_gen.families import QuestionFamilySpec, SamplingConstraint
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from app.tree.index import L1Node, L2Node, TreeIndex
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# ---------------------------------------------------------------------------
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# 题型 → 采样层级映射
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# ---------------------------------------------------------------------------
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_TASK_TYPE_TO_LEVEL: dict[str, int] = {
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# Level 3(细粒度帧级)
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"Action Recognition": 3,
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"Object Recognition": 3,
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# Level 2(片段/事件级)
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"Action Reasoning": 2,
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"Action Prediction": 2,
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"Action Sequence": 2,
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"Object Reasoning": 2,
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"Object Interaction": 2,
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"Scene Understanding": 2,
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"Event Reasoning": 2,
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"Causal Reasoning": 2,
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# Level 1(段落/场景级)
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"Temporal Reasoning": 1,
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"Spatial Reasoning": 1,
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}
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# ---------------------------------------------------------------------------
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# 数据类型
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# ---------------------------------------------------------------------------
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@dataclass(frozen=True)
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class AnchorContext:
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"""采样锚点上下文。
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属性:
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node_id: 锚节点 ID。
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level: 锚节点所在层级(1/2/3)。
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l2_id: 锚节点所属的 L2 节点 ID(若自身为 L2 则等于 node_id;
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若为 L1 则取其第一个 L2 子节点 ID)。
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"""
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node_id: str
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level: int
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l2_id: str
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@dataclass(frozen=True)
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class MaterialContext:
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"""采样素材上下文 — 出题所需的全部素材打包。
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属性:
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anchor: 采样锚点信息。
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source_nodes: 参与采样的节点 ID 元组。
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subtitle_sentences: 锚节点子树中收集的字幕句列表。
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frame_paths: 锚节点子树中可用的帧路径列表。
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cross_l2_texts: 跨 L2 段的上下文文本列表(仅 cross_l2_span 时填充)。
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"""
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anchor: AnchorContext
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source_nodes: tuple[str, ...]
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subtitle_sentences: list[str]
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frame_paths: list[str]
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cross_l2_texts: list[str]
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# ---------------------------------------------------------------------------
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# 内部索引辅助
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# ---------------------------------------------------------------------------
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def _find_l2_node(tree: TreeIndex, l2_id: str) -> tuple[L2Node, L1Node] | None:
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"""按 ID 定位 L2 节点及其父 L1。
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参数:
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tree: 三层树索引。
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l2_id: L2 节点 ID。
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返回:
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(L2Node, 父L1Node) 元组;未找到返回 None。
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"""
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for l1 in tree.roots:
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for l2 in l1.children:
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if l2.id == l2_id:
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return (l2, l1)
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return None
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def _find_l1_node(tree: TreeIndex, l1_id: str) -> L1Node | None:
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"""按 ID 定位 L1 节点。
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参数:
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tree: 三层树索引。
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l1_id: L1 节点 ID。
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返回:
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L1Node;未找到返回 None。
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"""
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for l1 in tree.roots:
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if l1.id == l1_id:
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return l1
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return None
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# ---------------------------------------------------------------------------
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# 公开辅助函数
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# ---------------------------------------------------------------------------
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def _validate_sampling_constraints(
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tree: TreeIndex, node_id: str, constraint: SamplingConstraint
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) -> bool:
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"""校验指定节点是否满足采样约束。
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根据节点层级自动判断检查范围:
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- L2 节点:检查其子 L3 的帧/字幕数量。
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- L1 节点:检查其下全部 L2/L3 的帧/字幕总数。
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- L3 节点:检查其所属 L2 的子树。
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参数:
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tree: 三层树索引。
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node_id: 待检查节点 ID。
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constraint: 采样约束条件。
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返回:
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True 表示满足所有约束,False 表示至少一项不满足。
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"""
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# Phase 1: 确定目标 L2 节点列表
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target_l2_nodes: list[L2Node] = []
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parent_l1: L1Node | None = None
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# 先尝试作为 L2
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result = _find_l2_node(tree, node_id)
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if result is not None:
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l2_node, parent_l1 = result
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target_l2_nodes = [l2_node]
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else:
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# 尝试作为 L1
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l1_node = _find_l1_node(tree, node_id)
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if l1_node is not None:
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target_l2_nodes = list(l1_node.children)
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parent_l1 = l1_node
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else:
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# 尝试作为 L3 — 找到其所属 L2
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for l1 in tree.roots:
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for l2 in l1.children:
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for l3 in l2.children:
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if l3.id == node_id:
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target_l2_nodes = [l2]
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parent_l1 = l1
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break
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if target_l2_nodes:
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break
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if target_l2_nodes:
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break
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if not target_l2_nodes:
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return False
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# Phase 2: 统计 L3 节点数
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total_l3 = sum(len(l2.children) for l2 in target_l2_nodes)
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if total_l3 < constraint.min_l3_nodes:
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return False
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# Phase 3: 检查帧路径可用性
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if constraint.require_frames:
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has_frame = any(l3.frame_path for l2 in target_l2_nodes for l3 in l2.children)
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if not has_frame:
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return False
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# Phase 4: 统计字幕数
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subtitle_count = 0
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for l2 in target_l2_nodes:
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if l2.card.subtitle:
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subtitle_count += 1
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for l3 in l2.children:
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if l3.card.subtitle:
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subtitle_count += 1
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if subtitle_count < constraint.min_subtitles:
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return False
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# Phase 5: 检查跨 L2 可用性
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return not (constraint.cross_l2_span and (parent_l1 is None or len(parent_l1.children) < 2))
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def _collect_subtitle_sentences(tree: TreeIndex, node_ids: tuple[str, ...]) -> list[str]:
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"""从指定节点集合中收集字幕句。
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遍历每个 node_id 对应的子树,提取非空字幕。
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对 L2 节点提取自身 + 子 L3 字幕;对 L1 提取下属全部。
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参数:
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tree: 三层树索引。
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node_ids: 待收集字幕的节点 ID 元组。
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返回:
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非空字幕句列表(去除空白后非空的字幕)。
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"""
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sentences: list[str] = []
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for nid in node_ids:
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# 尝试作为 L2
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result = _find_l2_node(tree, nid)
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if result is not None:
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l2_node, _ = result
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if l2_node.card.subtitle:
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sentences.append(l2_node.card.subtitle)
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for l3 in l2_node.children:
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if l3.card.subtitle:
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sentences.append(l3.card.subtitle)
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continue
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# 尝试作为 L1
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l1_node = _find_l1_node(tree, nid)
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if l1_node is not None:
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for l2 in l1_node.children:
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if l2.card.subtitle:
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sentences.append(l2.card.subtitle)
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for l3 in l2.children:
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if l3.card.subtitle:
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sentences.append(l3.card.subtitle)
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continue
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# 尝试作为 L3
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for l1 in tree.roots:
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for l2 in l1.children:
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for l3 in l2.children:
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if l3.id == nid and l3.card.subtitle:
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sentences.append(l3.card.subtitle)
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return sentences
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def _collect_cross_l2_context(tree: TreeIndex, anchor_l2_id: str, max_peers: int = 3) -> list[str]:
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"""收集锚 L2 的同级 L2 节点描述文本(跨 L2 上下文)。
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找到锚 L2 所属的 L1 父节点,取该父节点下除锚 L2 之外的其他 L2 描述。
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参数:
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tree: 三层树索引。
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anchor_l2_id: 锚 L2 节点 ID。
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max_peers: 最多返回的同级 L2 描述数量。
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返回:
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同级 L2 的 event_description 列表(最多 max_peers 条)。
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"""
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result = _find_l2_node(tree, anchor_l2_id)
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if result is None:
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return []
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_, parent_l1 = result
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peers: list[str] = []
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for l2 in parent_l1.children:
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if l2.id != anchor_l2_id:
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peers.append(l2.card.event_description)
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if len(peers) >= max_peers:
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break
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return peers
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# ---------------------------------------------------------------------------
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# 层级采样策略
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# ---------------------------------------------------------------------------
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def _sample_l3_node(
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tree: TreeIndex,
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used_node_ids: set[str],
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rng: random.Random,
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) -> tuple[str, str] | None:
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"""随机采样一个未使用的 L3 节点,返回 (l3_id, 所属l2_id)。
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参数:
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tree: 三层树索引。
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used_node_ids: 已用节点 ID 集合。
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rng: 随机数生成器。
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返回:
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(l3_id, l2_id) 元组;无候选返回 None。
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"""
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candidates: list[tuple[str, str]] = []
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for l1 in tree.roots:
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for l2 in l1.children:
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for l3 in l2.children:
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if l3.id not in used_node_ids:
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candidates.append((l3.id, l2.id))
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if not candidates:
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return None
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return rng.choice(candidates)
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def _sample_l2_node(
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tree: TreeIndex,
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used_node_ids: set[str],
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rng: random.Random,
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) -> tuple[str, str] | None:
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"""随机采样一个未使用的 L2 节点,返回 (l2_id, l2_id)。
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参数:
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tree: 三层树索引。
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used_node_ids: 已用节点 ID 集合。
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rng: 随机数生成器。
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返回:
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(l2_id, l2_id) 元组;无候选返回 None。
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"""
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candidates: list[str] = []
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for l1 in tree.roots:
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for l2 in l1.children:
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if l2.id not in used_node_ids:
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candidates.append(l2.id)
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if not candidates:
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return None
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chosen = rng.choice(candidates)
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return (chosen, chosen)
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def _sample_l1_node(
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tree: TreeIndex,
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used_node_ids: set[str],
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rng: random.Random,
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) -> tuple[str, str] | None:
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"""随机采样一个未使用的 L1 节点,返回 (l1_id, 首个子l2_id)。
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参数:
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tree: 三层树索引。
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used_node_ids: 已用节点 ID 集合。
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rng: 随机数生成器。
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返回:
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(l1_id, first_l2_id) 元组;无候选返回 None。
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"""
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candidates: list[tuple[str, str]] = []
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for l1 in tree.roots:
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if l1.id not in used_node_ids and l1.children:
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candidates.append((l1.id, l1.children[0].id))
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if not candidates:
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return None
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return rng.choice(candidates)
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def _collect_frame_paths(tree: TreeIndex, node_id: str) -> list[str]:
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"""收集节点子树下的所有可用帧路径。
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参数:
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tree: 三层树索引。
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node_id: 目标节点 ID。
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返回:
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帧路径列表。
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"""
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paths: list[str] = []
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# L2 节点
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result = _find_l2_node(tree, node_id)
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if result is not None:
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l2_node, _ = result
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for l3 in l2_node.children:
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if l3.frame_path:
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paths.append(l3.frame_path)
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return paths
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# L1 节点
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l1_node = _find_l1_node(tree, node_id)
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if l1_node is not None:
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for l2 in l1_node.children:
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for l3 in l2.children:
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if l3.frame_path:
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paths.append(l3.frame_path)
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return paths
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# L3 节点
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for l1 in tree.roots:
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for l2 in l1.children:
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for l3 in l2.children:
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if l3.id == node_id and l3.frame_path:
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paths.append(l3.frame_path)
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return paths
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return paths
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def _collect_source_nodes(tree: TreeIndex, node_id: str) -> tuple[str, ...]:
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"""收集节点子树涉及的全部节点 ID(包含自身)。
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参数:
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tree: 三层树索引。
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node_id: 目标节点 ID。
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返回:
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相关节点 ID 元组。
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"""
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ids: list[str] = [node_id]
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# L2 节点:加入子 L3
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result = _find_l2_node(tree, node_id)
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if result is not None:
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l2_node, _ = result
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for l3 in l2_node.children:
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ids.append(l3.id)
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return tuple(ids)
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# L1 节点:加入子 L2 + L3
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l1_node = _find_l1_node(tree, node_id)
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if l1_node is not None:
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for l2 in l1_node.children:
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ids.append(l2.id)
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for l3 in l2.children:
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ids.append(l3.id)
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return tuple(ids)
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# L3 节点:仅自身
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return tuple(ids)
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# ---------------------------------------------------------------------------
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# 主入口
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# ---------------------------------------------------------------------------
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def sample_material_v2(
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tree: TreeIndex,
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family_spec: QuestionFamilySpec,
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task_type: str,
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used_node_ids: set[str],
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rng: random.Random,
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*,
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max_attempts: int = 10,
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) -> MaterialContext:
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"""基于家族约束从视频树中采样素材上下文。
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||||
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||||
采样流程:
|
||||
1. 根据 task_type 确定采样层级
|
||||
2. 随机选取候选节点(排除 used_node_ids)
|
||||
3. 验证 SamplingConstraint 约束
|
||||
4. 约束不满足则重试(最多 max_attempts 次)
|
||||
5. 收集字幕、帧路径、跨 L2 上下文
|
||||
|
||||
参数:
|
||||
tree: 三层树索引。
|
||||
family_spec: 问题家族规格(含采样约束)。
|
||||
task_type: 任务类型字符串。
|
||||
used_node_ids: 本轮已用节点 ID 集合。
|
||||
rng: 可控随机数生成器。
|
||||
max_attempts: 最大尝试次数。
|
||||
|
||||
返回:
|
||||
MaterialContext 实例。
|
||||
|
||||
异常:
|
||||
RuntimeError: 耗尽 max_attempts 次尝试仍无法满足约束。
|
||||
KeyError: task_type 不在 _TASK_TYPE_TO_LEVEL 映射中。
|
||||
"""
|
||||
level = _TASK_TYPE_TO_LEVEL[task_type]
|
||||
constraint = family_spec.sampling
|
||||
|
||||
for attempt in range(max_attempts):
|
||||
# Phase 1: 按层级采样候选节点
|
||||
if level == 3:
|
||||
sampled = _sample_l3_node(tree, used_node_ids, rng)
|
||||
elif level == 2:
|
||||
sampled = _sample_l2_node(tree, used_node_ids, rng)
|
||||
else:
|
||||
sampled = _sample_l1_node(tree, used_node_ids, rng)
|
||||
|
||||
if sampled is None:
|
||||
logger.debug(
|
||||
"sample_material_v2 尝试 {}/{}: 无可用候选节点 (level={})",
|
||||
attempt + 1,
|
||||
max_attempts,
|
||||
level,
|
||||
)
|
||||
continue
|
||||
|
||||
node_id, l2_id = sampled
|
||||
|
||||
# Phase 2: 验证约束
|
||||
if not _validate_sampling_constraints(tree, node_id, constraint):
|
||||
logger.debug(
|
||||
"sample_material_v2 尝试 {}/{}: 约束违反 (node={})",
|
||||
attempt + 1,
|
||||
max_attempts,
|
||||
node_id,
|
||||
)
|
||||
continue
|
||||
|
||||
# Phase 3: 构造 AnchorContext
|
||||
anchor = AnchorContext(node_id=node_id, level=level, l2_id=l2_id)
|
||||
|
||||
# Phase 4: 收集素材
|
||||
source_nodes = _collect_source_nodes(tree, node_id)
|
||||
subtitle_sentences = _collect_subtitle_sentences(tree, (node_id,))
|
||||
frame_paths = _collect_frame_paths(tree, node_id)
|
||||
|
||||
# Phase 5: 跨 L2 上下文(仅 cross_l2_span 时收集)
|
||||
cross_l2_texts: list[str] = []
|
||||
if constraint.cross_l2_span:
|
||||
cross_l2_texts = _collect_cross_l2_context(tree, l2_id)
|
||||
|
||||
logger.debug(
|
||||
"sample_material_v2 成功: node={}, level={}, attempt={}/{}",
|
||||
node_id,
|
||||
level,
|
||||
attempt + 1,
|
||||
max_attempts,
|
||||
)
|
||||
|
||||
return MaterialContext(
|
||||
anchor=anchor,
|
||||
source_nodes=source_nodes,
|
||||
subtitle_sentences=subtitle_sentences,
|
||||
frame_paths=frame_paths,
|
||||
cross_l2_texts=cross_l2_texts,
|
||||
)
|
||||
|
||||
raise RuntimeError(
|
||||
f"sample_material_v2: 耗尽 max_attempts={max_attempts} 次尝试,"
|
||||
f"无法为 task_type='{task_type}' 满足家族 '{family_spec.name}' 的采样约束"
|
||||
)
|
||||
Reference in New Issue
Block a user