"""连续并发 gate 的前缀消费纯逻辑测试。""" from __future__ import annotations from app.harness.validate import GateSpec, _advance_prefix, _GateRun from core.evolution import GateParams from core.types import GeneratedQuestion, QuestionUnit def _mk_question(qid: str, task_type: str = "Action Reasoning") -> GeneratedQuestion: """构造最小可用的 single 题(字段以 core.types 真实定义为准,缺省值从简)。""" return GeneratedQuestion( question_id=qid, video_id="v1", task_type=task_type, question=f"q-{qid}", options=("A. x", "B. y"), answer="A", source_nodes=(), difficulty="easy", ) def _mk_unit(qid: str, task_type: str = "Action Reasoning") -> QuestionUnit: """由单条题目构造 single 单元(unit_id 回填为 question_id)。""" return QuestionUnit.from_single(_mk_question(qid, task_type)) def _mk_run(n_units: int) -> _GateRun: """构造含 n_units 个 single 单元的初始 gate 运行时状态。""" spec = GateSpec( task_type="Action Reasoning", target_file="action-reasoning.md", candidate_content="cand", base_skill_content="base", units=tuple(_mk_unit(f"q{i}") for i in range(n_units)), gate_run_prefix="r_e1_s0_gate_action-reasoning", ) return _GateRun.from_spec(spec) _PARAMS = GateParams( e_confirm=20.0, e_provisional=3.0, w_net_min=2, delta_min=0.02, lambda_dir=-0.642, e_rollback=10.0, ) def test_prefix_blocks_on_unresolved_head() -> None: """阶梯头部单元未配齐时,即使尾部全部配齐也一个都不消费。""" run = _mk_run(4) for i in (1, 2, 3): # 尾部三个先到 run.slots[i].base = False run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) assert run.n_used == 0 and run.w == 0 and run.verdict is None def test_prefix_consumes_in_ladder_order_after_head_arrives() -> None: """头部补齐后一次性顺序消费到最长已配齐前缀。""" run = _mk_run(4) for i in (0, 1, 2): run.slots[i].base = False run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) assert run.n_used == 3 and run.w == 3 and run.l == 0 assert [r["ladder_rank"] for r in run.evidence_rows] == [0, 1, 2] def test_freeze_on_terminal_verdict_stops_consumption() -> None: """过线即冻结,后续已配齐单元不再消费。 数值:W 连胜 L=0 时 E=(2^(W+1)-1)/(W+1),W=6→18.14<20,W=7→31.875≥20, 故 7 连胜恰好 confirmed 过线(Codex 复核)。 """ run = _mk_run(12) for i in range(12): run.slots[i].base = False run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) assert run.frozen and run.verdict is not None assert run.verdict.decision == "accept_confirmed" assert run.n_used == 7 # 第 7 个净胜恰好过线,早停不吃满 def test_tail_infra_reaches_terminal_not_continue() -> None: """尾部全 INFRA:剔除后须重判(n_remaining 归 0 → 题尽第四出口), verdict 不得停留在 continue(Codex plan 审 C1 回归锁)。""" run = _mk_run(4) run.slots[0].base = False run.slots[0].cand_per_q = {"q0": True} run.slots[1].base = True run.slots[1].cand_per_q = {"q1": True} for i in (2, 3): run.slots[i].base_infra = True run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) assert run.verdict is not None and run.verdict.decision != "continue" assert run.frozen def test_infra_unit_skipped_not_counted() -> None: """INFRA 单元(任一臂)剔除:不入 (W,L)、计入 n_excluded、前缀继续推进。 注意 futility 出口在小 n_remaining 下很敏感,用 6 单元(首个 INFRA、其余 5 个 W 翻转)保证消费全程不提前触发 futility:题尽走 accept_provisional 终态。 """ run = _mk_run(6) run.slots[0].base_infra = True run.slots[0].cand_per_q = {"q0": True} for i in range(1, 6): run.slots[i].base = False run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) assert run.n_excluded == 1 and run.n_used == 5 and run.w == 5 and run.l == 0 assert run.verdict is not None and run.verdict.decision == "accept_provisional" def test_all_infra_leaves_verdict_none() -> None: """全部单元被剔除:verdict 保持 None、frozen 保持 False——终态由调度编排层 (Task 3 的 validate_skills_concurrent)检测 verdict None 并 raise,本函数不管。""" run = _mk_run(3) for i in range(3): run.slots[i].base_infra = True run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) assert run.verdict is None and not run.frozen and run.n_excluded == 3 and run.prefix_ptr == 3 def test_repeated_calls_are_idempotent() -> None: """部分前缀消费后重复调用不改变状态;补齐剩余单元后再调用正常推进。""" run = _mk_run(4) for i in (0, 1): run.slots[i].base = False run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) snapshot = (run.n_used, run.w, run.l, run.prefix_ptr, len(run.evidence_rows)) _advance_prefix(run, _PARAMS) _advance_prefix(run, _PARAMS) assert (run.n_used, run.w, run.l, run.prefix_ptr, len(run.evidence_rows)) == snapshot for i in (2, 3): run.slots[i].base = False run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) assert run.n_used > snapshot[0] and run.prefix_ptr > snapshot[3] def test_frozen_run_call_is_noop() -> None: """frozen 后再调用是 no-op:不再消费已配齐单元、证据不再追加。""" run = _mk_run(12) for i in range(12): run.slots[i].base = False run.slots[i].cand_per_q = {f"q{i}": True} _advance_prefix(run, _PARAMS) assert run.frozen and run.n_used == 7 n_evidence = len(run.evidence_rows) _advance_prefix(run, _PARAMS) assert run.n_used == 7 and len(run.evidence_rows) == n_evidence def test_ties_hit_futility_early_and_freeze() -> None: """全打平(无翻转对)时 futility 出口尽早触发并冻结——早停语义(数值:W=L=0 时乐观 E = E(n_remaining, 0),n 小易